# Line slope calculator 3x+7y=37

**Straight line given by points A[3; 4] and B[10; 1]**

## Calculation:

**Slope-intercept form of line:**y = -0.4286x+5.2857

**Canonical form of the line equation:**3x+7y-37 = 0

**Parametric form of the line equation:**

x = 7t+3

y = -3t+4 ; t ∈ R

**Slope:**m = -0.4286

**Slope angle of line: φ =**-23°11'55″ = -0.4049 rad

**X intercept:**x

_{0}= 12.3333

**Y intercept:**y

_{0}= q = 5.2857

**Distance line from the origin:**d

_{0}= 4.8583

**The length of the segment AB: |AB| =**7.6158

**Vector: AB =**(7; -3)

**Normal vector: n =**(3; 7)

**Midpoint of the segment AB: M =**[6.5; 2.5]

**Perpendicular Bisector equation:**7x-3y-38 = 0

**Vector OA = (3; 4) ; |OA| = 5**

**Vector OB = (10; 1) ; |OB| = 10.0499**

**Scalar product OA .OB = 34**

**Angle ∠ AOB = 47°25'10″ = 0.8276 rad**